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Home/ Questions/Q 753593
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T14:54:55+00:00 2026-05-14T14:54:55+00:00

I’m not a professional programmer, so please don’t hesitate to state the obvious. My

  • 0

I’m not a professional programmer, so please don’t hesitate to state the obvious.

My goal is to use a std::multiset container (typedef EventMultiSet) called currentEvents to organize a list of structs, of type Event, and to have members of class Host occasionally add new Event structs to currentEvents. The structs are supposed to be sorted by one of their members, time. I am not sure how much of what I am trying to do is legal; the g++ compiler reports (in “Host.h”) “error: ‘EventMultiSet’ has not been declared.” Here’s what I’m doing:

// Event.h
struct Event {
  public:

  bool operator < ( const Event & rhs ) const {
  return ( time < rhs.time );
 }

 double time;
 int eventID;
 int hostID;
};

// Host.h
...
void calcLifeHist( double, EventMultiSet * ); // produces compiler error
...
void addEvent( double, int, int, EventMultiSet * ); // produces compiler error

// Host.cpp
#include "Event.h"
...

// main.cpp
#include "Event.h"
...
typedef std::multiset< Event, std::less< Event > > EventMultiSet;
EventMultiSet currentEvents;
EventMultiSet * cePtr = &currentEvents;
...

Major questions

  1. Where should I include the EventMultiSet typedef?
  2. Are my EventMultiSet pointers obviously problematic?
  3. Is the compare function within my Event struct (in theory) okay?

Thank you very much in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-14T14:54:56+00:00Added an answer on May 14, 2026 at 2:54 pm
    1. The compiler errors are simply because your typedef is in the wrong place – only main.cpp knows about it. It looks like you probably want it in Event.h, which both of the others include.

    2. I’m not sure exactly what you’re asking – but possibly you want to pass by reference not by pointer?

    3. I don’t see anything wrong with it – though you might want to provide the other comparisons (>, <=, …) too.

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