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Home/ Questions/Q 8661355
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T16:28:41+00:00 2026-06-12T16:28:41+00:00

I’m not an expert in PHP even though I’ve been working with some stuff,

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I’m not an expert in PHP even though I’ve been working with some stuff, copying and pasting from here and there, well I want to ask something that I can not find and that I don’t have the slightest idea on how to implement it.

For instance, at a table like this:

    +------+-----+
    |NAME  |BIRTH|
    +------+-----+
    |John  |1980 |
    |Carl  |1982 |
    |Alice |1990 |
    |June  |1994 |
    |Rob   |1998 |
    |Alice |1998 |
    |John  |2000 |
    |Alice |2001 |
    |Etc.  |     |
    +------+-----+

I do different queries, like these below (and I could keep doing queries with any combination of years):

  1. Select * from table where BIRTH between 1980 and 1990
  2. Select * from table where BIRTH between 1980 and 2001
  3. Select * from table where BIRTH between 1990 and 2001

So I will get 3 different tables, and from those tables I need to count the different contents,
for instance, from the table obtained with the query1 I need to obtain:

   John = 1
   Carl = 1
   Alice = 1

from table of query2:

   John = 2
   Carl = 1
   Alice = 3
   June = 1
   Rob =1

from table of query3:

   Alice = 3
   John = 1
   Carl = 1
   June = 1
   Rob =1

And remember the big table has 700 records, so it could appear any new name, and I need to print out the result in the same way:

   Alice = 3
   John = 1
   NewName = 1
   June = 1
   Rob =1

My final goal is do percentages in relation to the obtained table, and not to the total of registers.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T16:28:42+00:00Added an answer on June 12, 2026 at 4:28 pm

    You should do it in SQL, not in PHP :

    select NAME, count(1)
    from TABLE
    where condition
    group by NAME
    

    This will produce the exact view you want. Names as first column, the count on the second.

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