Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7066663
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T05:06:29+00:00 2026-05-28T05:06:29+00:00

I’m not awesome enough to write a chat application, and I’m trying to get

  • 0

I’m not awesome enough to write a chat application, and I’m trying to get one to work, and I’ve recently downloaded one from here, it’s pretty good so far, as I’ve tested it out on XAMPP, but I have a slight problem. I’m trying to generate a list of online users to give it a more practical application-like feel, but the problem with that, is I have no clue how to do it easily.

When users login to my site, a session named g_username is created, (the chat says ‘username’, but I’ll fix that) and from what I see so far, the easiest method would be to store their username in a database called OnlineUsers and call that data via Ajax, but, the other problem, is that it’s session based, and sometimes the users can just leave, without logging out, and I intended to run a script to logout the user from both the OnlineUsers table, and by deleting the session.

If they leave without logging out, they’d be online forever! I could potentially suffix a bit of code on every page, that toggled an ajax event on page close, the event being a script that kills their OnlineUsers table record, but then again, that would load the server with useless queries as users jump between pages, as far as I’m aware.

Creating my entire site in Ajax isn’t really an option, as it’s a load of different sites combined in to 1 ‘place’ with a social ‘layer’ (if you will) from a social service.

Does anyone see a way to do this that would make sense, and be easy to integrate, and do with Apache, without command line access?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-28T05:06:30+00:00Added an answer on May 28, 2026 at 5:06 am

    You could so something like storing a timestamp of the users last action in a database, comparing that timestamp when outputting online users and making sure that it was done at most 1 min ago.

    Run on all/vital pages:
    (Deciding if the last action is outdated, you could also check if it was done for one minute ago to reduce the database-load)

    if($user['lastAction'] < time()) {
       //update into database, last action is outdated
    }
    

    When calculating the amount of users online and is within the loop of each timestamp

    //If the users last action was within a minute, the user is most likely online    
    if(($row['lastAction']- time()) > 60*60)
           //count user as online
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm trying to decode HTML entries from here NYTimes.com and I cannot figure out
For some reason, after submitting a string like this Jack’s Spindle from a text
Basically, what I'm trying to create is a page of div tags, each has
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I am trying to understand how to use SyndicationItem to display feed which is
I am currently running into a problem where an element is coming back from
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
I have a text area in my form which accepts all possible characters from
I need a function that will clean a strings' special characters. I do NOT
Does anyone know how can I replace this 2 symbol below from the string

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.