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Home/ Questions/Q 8132687
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T09:24:20+00:00 2026-06-06T09:24:20+00:00

I’m not completely sure how to do this in C: char* curToken = strtok(string,

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I’m not completely sure how to do this in C:

char* curToken = strtok(string, ";");
//curToken = "ls -l" we will say
//I need a array of strings containing "ls", "-l", and NULL for execvp()

How would I go about doing this?

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  1. Editorial Team
    Editorial Team
    2026-06-06T09:24:21+00:00Added an answer on June 6, 2026 at 9:24 am

    Since you’ve already looked into strtok just continue down the same path and split your string using space (' ') as a delimiter, then use something as realloc to increase the size of the array containing the elements to be passed to execvp.

    See the below example, but keep in mind that strtok will modify the string passed to it. If you don’t want this to happen you are required to make a copy of the original string, using strcpy or similar function.

    char    str[]= "ls -l";
    char ** res  = NULL;
    char *  p    = strtok (str, " ");
    int n_spaces = 0, i;
    
    
    /* split string and append tokens to 'res' */
    
    while (p) {
      res = realloc (res, sizeof (char*) * ++n_spaces);
    
      if (res == NULL)
        exit (-1); /* memory allocation failed */
    
      res[n_spaces-1] = p;
    
      p = strtok (NULL, " ");
    }
    
    /* realloc one extra element for the last NULL */
    
    res = realloc (res, sizeof (char*) * (n_spaces+1));
    res[n_spaces] = 0;
    
    /* print the result */
    
    for (i = 0; i < (n_spaces+1); ++i)
      printf ("res[%d] = %s\n", i, res[i]);
    
    /* free the memory allocated */
    
    free (res);
    

    res[0] = ls
    res[1] = -l
    res[2] = (null)
    
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