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Home/ Questions/Q 9226139
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T04:45:28+00:00 2026-06-18T04:45:28+00:00

I’m not getting any data, and I’ve checked my dad which should match up

  • 0

I’m not getting any data, and I’ve checked my dad which should match up

I have two tables, likes and user_follow
I’m trying to tie the two tables by an id.

Table – Column

likes – idlikes, iduser, information
user_follow – iduser_follow, iduser_follower, iduser_following

$following = $dbh -> prepare("SELECT L.* FROM likes L JOIN user_follow F ON F.iduser_following = L.iduser WHERE F.iduser_follower = ?");
$following->execute(array($_SESSION['user_auth']));
while($row_following = $following->fetch(PDO::FETCH_ASSOC)){
     $id_1 = $row_following['L.information']; // get id of user that i'm following
     echo $id_1;
}

So if i’m following someone, i should be able to display information associated with whomever I’m following.

I don’t get any errors, it just doesn’t echo out anything?


Sample Data

user_follow

iduser_follow           iduser_follower            iduser_following
     1                         2                        3
     2                         2                        4

likles

  idlikes                   iduser                  information
     1                         3                        info1
     2                         3                        info2

So, I should output info1 and info2, assuming that $_SESSION[‘user_auth’] = 2, correct?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T04:45:29+00:00Added an answer on June 18, 2026 at 4:45 am
    SELECT  b.*
    FROM    user_follow a
            INNER JOIN likes b
                ON a.iduser_following = b.iduser
    WHERE   a.iduser_follow = 'myuserID' AND
            iduser_following = 'followingID'
    

    and fetch value

    $id_1 = $row_following['information'];
    
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