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Home/ Questions/Q 6646901
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T00:28:26+00:00 2026-05-26T00:28:26+00:00

I’m not new to Java, but have not dealt with Regex and Patterns before.

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I’m not new to Java, but have not dealt with Regex and Patterns before. What I’m looking to do is take a string like

"Class: " + data1 + "\nFrom: " + data2 + " To: " + data3 + "\nOccures: " + data4 + " In: " + data5 + " " + data6;

and pull out only data_1 to data_n.
I appreciate any help.

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  1. Editorial Team
    Editorial Team
    2026-05-26T00:28:26+00:00Added an answer on May 26, 2026 at 12:28 am

    Use this regex:

    Pattern pattern = Pattern.compile("Class: (.+?)\nFrom: (.+?) To: (.+?)\nOccures: (.+?) In: (.+?) (.+?)");
    Matcher matcher = pattern.matcher(yourInputString);
    if (matcher.find())
    {
         String data1 = matcher.group(1);
         String data2 = matcher.group(2);
         String data3 = matcher.group(3);
         String data4 = matcher.group(4);
         String data5 = matcher.group(5);
         String data6 = matcher.group(6);
    } else
    {
        // String didn't match the specified format
    }
    

    Explanation:

    .+? will match any character for undefined times, but non-greedy.
    (), using brackets will create a group. A group is given an index starting by 1 (since group 0 is the entire match)

    So, (.+?) will creates groups of any character.

    And what the matcher does, is searching for the whole pattern somewhere in the input string. But since you specified the format, we know exactly how your entire string is going to look like. The only thing you have to do is copy the format and replace the data you want to extract with “something” (.+?), which you give an index by creating a group of it.

    Afterwards, the matcher will try to find the pattern (done by matcher.find()) and you ask them what the content is of the groups 1 up to 6.

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