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Home/ Questions/Q 714919
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T05:07:44+00:00 2026-05-14T05:07:44+00:00

I’m not php expert and I don’t know what’s the difference(1) between a and

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I’m not php expert and I don’t know what’s the difference(1) between a and b.

a.)eval('return "'.base64_decode("encoded_text").'";')

b.)base64_decode("encoded_text")

-I THINK, a is php code and b is just string. And my other question is:

What is the difference(2) between c and d?

c.)eval('return "'.base64_decode("encoded_text").'";')

d.)eval(base64_decode("encoded_text"))

So I have 2 questions. Who can answer/help ?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-14T05:07:44+00:00Added an answer on May 14, 2026 at 5:07 am

    Let’s label your 2 cases as Case X (part a and b) and Y (part c and d).

    Case X

    For this, both of the parts have no difference from each other. In fact, part a has some redundancy.

    If you evaluate them slowly, you will notice how redundant it is:

    Part a
    In this part, the difference is that you add the eval statement with return in the string for evaluation.

    1. echo eval('return "'.base64_decode("encoded_text").'";');
    2. echo eval('return "decoded_text";')'
    3. echo "decoded_text";

    Part b

    1. echo base64_decode("encoded_text");
    2. echo "decoded_text";

    Case Y

    For this, there’s grave difference.

    Part c

    1. echo eval('return "'.base64_decode("encoded_text").'";');
    2. echo eval('return "decoded_text";')'
    3. echo "decoded_text";

    Part d

    1. echo eval(base64_decode("encoded_text"));
    2. echo eval("decoded_text"); – there may be a syntax error here, because decoded_text may or may not be proper PHP code.
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