I’m not so good with bitwise operators so please excuse the question but how would I clear the lower 16 bits of a 32-bit integer in C/C++?
For example I have an integer: 0x12345678 and I want to make that: 0x12340000
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
I’m not so good with bitwise operators so please excuse the question but how would I clear the lower 16 bits of a 32-bit integer in C/C++?
For example I have an integer: 0x12345678 and I want to make that: 0x12340000
To clear any particular set of bits, you can use bitwise AND with the complement of a number that has 1s in those places. In your case, since the number 0xFFFF has its lower 16 bits set, you can AND with its complement:
If you wanted to set those bits, you could instead use a bitwise OR with a number that has those bits set:
And, if you wanted to flip those bits, you could use a bitwise XOR with a number that has those bits set:
Hope this helps!