Question

I’m not sure if my title is really correct. I’ve looked around and searched but not found anything so please forgive me if my problem has been answered already.

What I would like to do is call a function but not have to come back to the calling line of code. e.g

public static void temp(obj) {
   switch (obj.id) {
     case "1" :
       if(blah) {
         obj.id = "2";
         temp(obj);
       }
       break;
     case "2" :
       obj.response = "done";
       break;
   }
}

so basically I dont want to eventually come back to my temp(obj) in the first case and fully pass control. Does this make sense, is it even possible and my architecture is all wrong?

Thank you for your time.

Answer 1

Let me see if I understand the question:

You’ve got a function Foo(), which calls function Bar(). (I wanted to remove the recursion you had in your example for simplicity, please correct me if that was important.) When function Bar() returns, you want control to pass not back to Foo(), but to Foo’s caller?

This is probably possible in lower-level languages, like C, by hacking the stack and not placing Foo()‘s return address there, so that when Bar() tried to return, it would jump to Foo’s caller instead.

However, in C#, no. The call stack is a stack, and control will pass back in order. The only thing you can do would be to put a return statement after each call to Bar().

Edit:

“recursive calls without them being recursive”

How about this:

bool doItAgain = true;
while(doItAgain)
{
    doItAgain = false;

    // process, with your switch statement or whatever.

    if(...)
    {
        doItAgain = true;
        continue; // if necessary, skip any code after this statement. May not be necessary if you have things set up right.
    }
}