I’m not sure whats wrong with the program below, but it doesn’t print each and every language once, but randomly some more often, some more less and some wont print
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
char *messages[] = {
"English: Hello World!",
"French: Bonjour, le monde!",
"Spanish: Hola al mundo",
"Klingon: Nuq neH!",
"German: Guten Tag, Welt!",
"Russian: Zdravstvytye, mir!",
"Japan: Sekai e konnichiwa!",
"Latin: Orbis, te saluto!"
};
#define NUM_MESSAGES (sizeof( messages ) / sizeof( char* ))
void *PrintHello( void *messageid )
{
pthread_t taskid;
int *id_ptr, message_num;
taskid = pthread_self();
printf( "This is thread with ID %lu.\n", taskid );
message_num = *((int *) messageid);
printf( "%s \n", messages[message_num] );
pthread_exit( NULL );
}
int main( int argc, char *argv[] )
{
pthread_t threads[NUM_MESSAGES];
int rc, i;
for( i = 0; i < NUM_MESSAGES; i++ ) {
void * argument = (void*) &i;
rc = pthread_create( &threads[i], NULL, PrintHello, argument );
if( rc ) {
printf( "ERROR; return code from pthread_create() is %d\n", rc );
exit( -1 );
}
}
for( i = 0; i < NUM_MESSAGES; i++ ) {
pthread_join( threads[i], NULL );
}
pthread_exit( NULL );
}
I guess the problem is somehow connected with the argument pointer. I tried to lock different parts but with no success.
You’re passing the address of the variable
i, which the main thread keeps changing. So you’re at the mercy of scheduling: will anyone changeibefore your thread has a chance to run ?Instead, you could try directly passing the string, greatly simplifying the code:
There’s another, poorer alternative where you pass the actual value of
ias the argument (not its address).