Question

I’m not sure why this is causing me trouble, I think I did it earlier in a test and it worked fine.

I get some user input using cin then pass this to another method as a char. I then just wanted to say:

if(userInput == '!'){
     //do Something
}

But it didn’t get it, so I tried defining a char as:

const char myChar ='\u033f';


if(guess == myChar){
    exit(0);

}

But this just gives me a few compile errors even thou I’m getting that from another StackOverflow thread.

I must be misunderstanding something fundamental here, could someone enlighten me?

TIA

Answer 1

The following example works for me:

#include <iostream>

int main() {
    const char myChar = '!';
    char guess;
    std::cin >> guess;
    if (guess == myChar) {
        exit(0);
    }
    std::cerr << "No!" << std::endl;
}

Perhaps if your question is clarified a little more, I can edit this answer to be a little more complete.