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Home/ Questions/Q 3970214
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T04:03:34+00:00 2026-05-20T04:03:34+00:00

I’m not sure why this is happening – hoping someone can explain it! I

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I’m not sure why this is happening – hoping someone can explain it!

I have a base class called BaseRequest with this in it:

protected int cartNumber;

I have a derived class, which inherits BaseRequest. It has a public field and constructor as follows:

public int currentCartNumber;

public ExtendedBaseRequest(int cartNumber)
{
   currentCartNumber = cartNumber;
}

Yes, I know it’s a bit silly to have a parameter with the same name as the protected field in the base class, but I didn’t notice it until now!

This compiles and runs, but the public currentCartNumber value in the derived class is not set as it uses the value from the base class, which is always zero as initialised.

Shouldn’t the compiler moan about this because the declaration of cartNumber in the constructor’s signature has the same name as the one in the base?

Looking forward to hearing from you.

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  1. Editorial Team
    Editorial Team
    2026-05-20T04:03:34+00:00Added an answer on May 20, 2026 at 4:03 am

    Your analysis of what’s happening is incorrect. There’s something else going on here.

    Are you sure that you’re not passing 0 into the constructor?

    The unqualified cartNumber will always refer to the parameter. The inherited field would need to be qualified with this or base.

    In the code shown in the question, the statement currentCartNumber = cartNumber will assign the value of the cartNumber parameter to the currentCartNumber field.

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