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Asked: 2026-06-05T21:44:47+00:00

I’m not too sure what’s going on here but I’m trying to echo a

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I’m not too sure what’s going on here but I’m trying to echo a value from mysql and when I do, it just shows double for some reason

Code:

$result = MySqlQuery('SELECT value FROM table WHERE id=1');
$value = mysqli_fetch_assoc($result);

echo implode($value);

It displays 7373, the value is 73 in the DB.
I also tried echoing * instead of value, it also displays the entire row double.

Removing the echo there just displays nothing anymore so it’s not like it’s being echoed through another function either so I’m confused

Also the MySqlQuery() function is used by pretty much everything else on the site where it doesn’t display double results as well

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1 Answer

  1. Editorial Team

    mysqli_fetch_array returns an array with twice as many elements as the columns you select by default (each column is represented twice). I assume that the mysqli_fetch_assoc in your code is a typo.

    To solve the problem, either use mysqli_fetch_assoc instead or pass one of MYSQLI_ASSOC and MYSQLI_NUM as the second parameter to mysqli_fetch_array. As a rule of thumb, use mysqli_fetch_assoc unless you know you need something else.

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