Question

I’m open to

eclipse –> new –> dynamic web
project –> in target runtime –> new
Apache Tomcat v6.0 and establish mark
Create a new local server –> next
Browse establish way
C:\dev\apache-tomcat-6.0.29-windows-x86\apache-tomcat-6.0.29
–> finish –> in new dynamic project finish

in Java Resources : src new class

java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class f extends HttpServlet 
{
    public void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException 
    {
        resp.setContentType("text/html;charset=utf-8");
        PrintWriter pw = resp.getWriter();
        pw.println("<H1>Hello, world! или Привет мир</H1>");
    }
}

–>server start in save resources s.java been modified. Save changes? I’m yes. –> Run servlet/s –> result
HTTP Status 404 – /s/servlet/s

---

type Status report

message /s/servlet/s

description The requested resource (/s/servlet/s) is not available.

---

Apache Tomcat/6.0.14

How and when I’m error?
How need the create right?

I’m sorry, bad English. explain most clear and distinctly

Answer 1

Have you checked the web.xml deployment descriptor?
There you have to define your servlet mapping, or otherwise the servlet container won’t have notice of the servlet.

Example:

 <?xml version="1.0" encoding="UTF-8"?>
 <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

   <!-- Servlet definition -->
    <servlet>
        <servlet-name>s</servlet-name>
        <servlet-class>your.package.path.s</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

   <!-- servlet mapping -->
   <servlet-mapping>
       <servlet-name>s</servlet-name>
       <url-pattern>/myServlet</url-pattern>
   </servlet-mapping>
<web-app>

And now, you can access it with your mapped path (“/<contextPath>/myServlet“) or with the default invoker (“/<contextPath>/servlet/s“).