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Home/ Questions/Q 970089
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T02:45:00+00:00 2026-05-16T02:45:00+00:00

I’m opening a new thread based on this how to store an array in

  • 0

I’m opening a new thread based on this how to store an array in jquery cookie?. I’m using function from almog.ori :

var cookieList = function(cookieName) {
//When the cookie is saved the items will be a comma seperated string
//So we will split the cookie by comma to get the original array
var cookie = $.cookie(cookieName);
//Load the items or a new array if null.
var items = cookie ? cookie.split(/,/) : new Array();

//Return a object that we can use to access the array.
//while hiding direct access to the declared items array
//this is called closures see http://www.jibbering.com/faq/faq_notes/closures.html
return {
    "add": function(val) {
        //Add to the items.
        items.push(val);
        //Save the items to a cookie.
        $.cookie(cookieName, items);
    },
    "clear": function() {
        //clear the cookie.
        $.cookie(cookieName, null);
    },
    "items": function() {
        //Get all the items.
        return items;
    }
  }
}

to grab an array of index element on click event :

var list = new cookieList("test");
$(img).one('click', function(i){
while($('.selected').length < 3) {
    $(this).parent()
        .addClass("selected")
        .append(setup.config.overlay);

    //$.cookie(setup.config.COOKIE_NAME, d, setup.config.OPTS);
    var index = $(this).parent().index();

    // suppose this array go into cookies.. but failed
    list.add( index );
    // this index goes in array
    alert(list.items());

    var count = 'You have selected : <span>' + $('.selected').length + '</span> deals';
    if( $('.total').length ){
        $('.total').html(count);
    }

} 
});

When I getting list of items, it return null but when I alert in onclick event, eventually it push value into that array. But when I’d tried to retrieve back cookie, it return null. Help please…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T02:45:01+00:00Added an answer on May 16, 2026 at 2:45 am

    This line:

    $.cookie(cookieName, items);
    

    Should create the string from the array as well, like this:

    $.cookie(cookieName, items.join(','));
    

    This is so that when loading the array via cookie.split(/,/), it gets a string it expects (comma-delimited).

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