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Home/ Questions/Q 7189095
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T19:13:41+00:00 2026-05-28T19:13:41+00:00

I’m passing as parameter an id to a javascript function, because it comes from

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I’m passing as parameter an id to a javascript function, because it comes from UI, it’s left zero padded. but it seems to have (maybe) “strange” behaviour?

    console.log(0000020948);  //20948
    console.log(0000022115);   //9293 which is 22115's octal 
    console.log(parseInt(0000022115, 10));  // 9293 which is 22115's octal
    console.log(0000033959);  //33959
    console.log(20948);  //20948
    console.log(22115); //22115
    console.log(33959); //33959

how can I make sure they are parsing to right numebr they are? (decimal)

EDIT:

just make it clearer:

those numbers come from the server and are zero padded strings. and I’m making a delete button for each one.

like:

function printDelButton(value){
          console.log(typeof value);  //output string 
  return '<a href="#" onclick="deleteme('+value+')"><img src="images/del.png"></a>'
}

and 

function printDelButton(value){
console.log(typeof value); //output numeric
    console.log(value);   //here output as octal .... :S
 }

I tried :

console.log(parseInt(0000022115, 10));  // 9293 which is 22115's octal

and still parsing as Octal

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T19:13:42+00:00Added an answer on May 28, 2026 at 7:13 pm

    If you receive your parameters as string objects, it should work to use

     parseInt(string, 10)
    

    to interpret strings as decimal, even if they are beginning with 0.

    In your test, you pass the parseInt method a number, not a string, maybe that’s why it doesn’t return the expected result.

    Try

     parseInt('0000022115', 10)
    

    instead of

    parseInt(0000022115, 10)
    

    that does return 221115 for me.

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