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Home/ Questions/Q 7731549
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T06:30:27+00:00 2026-06-01T06:30:27+00:00

I’m performing an ajax call to grab an HTML page from the server; ajax

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I’m performing an ajax call to grab an HTML page from the server; ajax call looks like this:

function loadHtml() {
    $.ajax({
          type          :  'GET',
          async         :  false,
          url           :  'my.html',
          contentType   :  'text/html',
          dataType      :  'html',
          success       :  function(data) {
              loadedHtml = data; // the loadedHtml variable is global
          }
    });
}

Later, I’d like to display this html after modifying it somewhat.


Attempt 1

I tried this, but the resulting screen shows nothing at all (body contains no html).

var myContent = $(loadedHtml).find('#test1').text("Modified!");
$('body').html(myContent);

Attempt 2

I also tried this, but the resulting screen just shows the original content of loadedHtml.

var myContent = $(loadedHtml);
myContent.find('#test1').text("Modified!");
$('body').html(myContent);

Original Html

Here’s the original content of loadedHtml from my.html

<div id="test1" style="color: white;"> Working! </div>

What am I doing wrong?


UPDATES

  1. This is a simple example I’m trying to get to work before adding the complexity of what I really need to be doing. So, using a simple string replace on the loadedHtml variable before inserting it into the DOM is not something that will work for me.
  2. I’ve updated my code to show the ajax call is synchronous. the loadedHtml variable does in fact contain the html from the server by the time I get to the point I’m trying to modify it.
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T06:30:29+00:00Added an answer on June 1, 2026 at 6:30 am

    You misuse the find function:

    Given a jQuery object that represents a set of DOM elements, the .find() method allows us to search through the descendants of these elements in the DOM tree and construct a new jQuery object from the matching elements. The .find() and .children() methods are similar, except that the latter only travels a single level down the DOM tree.

    It search only descendants, In your case #test1 isn’t a child…

    so this:

    $('<div id="test1" style="color: white;"> Working! </div>').find('#test1')
    

    Won’t grab the test1 element, it’s not a descendant.

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