Question

I’m php developer starting to get heavier into ajax and I’ve come across a problem I am not sure how to solve.

I am creating a form on the fly like this:

function addSearchResult(label, tz) {
    var html = '';
    html += '<div>'
    html += '<form id="product-form" >';
    html += '<div class="clock">'
    html += '<div class="hour"></div>'
    html += '<div class="min"></div>'
    html += '<div class="sec"></div>'
    html += '<input type="text" id="label" name="Label" placeholder="Label">'
    html += '</div>'
    html += '<div class="city">GMT</div>'
    html += '<a href="#" class="whiteButton submit" id="view-product-button" >View</a>'
    html += '</form>'
    html += '</div>'
    var insert = $(html);
    $('#search-results').append(insert.data('tz_offset', tz).find('.city').html(label).end());
}

And I am reading the form results like this:

$('#product-form').submit(function() {
    alert('OK');
    addProduct('Test Value', 'Test Produlct');
    $('input').blur();
    $('#add .cancel').click();
    this.reset();
    return false;
});

The problem is, it does not work. If I put the form directly in the html it works fine. But adding it through ajax, it will not pick up that the form exist.

How should I go about solving this problem?

Answer 1

Using the shortcut event handlers (eg submit() or click()) only works for elements which are placed in the DOM on page load.

For dynamically added elements, you need to use delegate(), or on() for jQuery 1.7+. Try this:

< jQ 1.7

$('#search-results').delegate('#product-form', 'submit', function() {
    // rest of your code
});

jQ 1.7+

$('#search-results').on('submit', '#product-form', function() {
    // rest of your code
});