Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7648025
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T10:36:27+00:00 2026-05-31T10:36:27+00:00

I’m playing around with Ruby to do some file versioning for me. I have

  • 0

I’m playing around with Ruby to do some file versioning for me. I have a string 2.0.0.65 . I split it up, increment the build number (65 –> 66) then I want to replace the 65 with the 66. In this replace though, I only want to replace the last match of the string. What’s the best way in Ruby to do this?

 version_text = IO.read('C:\\Properties')
 puts version_text
 version = version_text.match(/(\d+\.\d+\.\d+\.\d+)/)[1]
 puts version
 build_version = version.split('.')[3]
 puts build_version
 incremented_version =  build_version.to_i + 1
 puts incremented_version`
 ...
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-31T10:36:29+00:00Added an answer on May 31, 2026 at 10:36 am

    If you just want to increment the integer at the very end of a string then try this:

    s = '2.0.0.65'
    s.sub(/\d+\Z/) {|x| x.to_i + 1} # => '2.0.0.66'
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have just tried to save a simple *.rtf file with some websites and
I want to count how many characters a certain string has in PHP, but
For some reason, after submitting a string like this Jack’s Spindle from a text
I have a French site that I want to parse, but am running into
I want use html5's new tag to play a wav file (currently only supported
i want to parse a xhtml file and display in UITableView. what is the
I have a reasonable size flat file database of text documents mostly saved in
I have some data like this: 1 2 3 4 5 9 2 6
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I would like to count the length of a string with PHP. The string

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.