Question

I’m playing around with some keyboard development and try to show a pop-up dialog when a certain key is pressed

if (primaryCode == -301) {
            AlertDialog mDialog = new AlertDialog.Builder(CONTEXT)
            .setTitle("My dialog")
            .setMessage("Lets do it.")
            .setPositiveButton("ok", null).create();
             mDialog.show();
}

However, the problem is the CONTEXT part. In a normal application it would just be this. I also tried getApplicationContext() and getBaseContext(), but neither of those works -> keyboard crashes.

android.view.WindowManager$BadTokenException:
Unable to add window — token null is
not for an application

So I’m wondering if I have to do something with InputConnection:

The InputConnection interface is the
communication channel from an
InputMethod back to the application
that is receiving its input. It is
used to perform such things as reading
text around the cursor, committing
text to the text box, and sending raw
key events to the application.

So far I wasn’t able to figure out how. I definitely know it’s possible, since I have seen it before. I someone could point me in the right direction that would definitely be appreciated.

---

Update:

To provide a better picture of what I try to achieve I uploaded a screenshot of the Swype keyboard, which does exactly that: showing a pop-up dialog when a special key gets pressed on the keyboard.

Answer 1

Peace be upon those who follow the guidance,

solution :

AlertDialog dialog;
//add this to your code
       dialog = builder.create();
        Window window = dialog.getWindow(); 
        WindowManager.LayoutParams lp = window.getAttributes();
            lp.token = mInputView.getWindowToken();
            lp.type = WindowManager.LayoutParams.TYPE_APPLICATION_ATTACHED_DIALOG;
            window.setAttributes(lp);
            window.addFlags(WindowManager.LayoutParams.FLAG_ALT_FOCUSABLE_IM);
//end addons
alert.show();

good luck.