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Asked: 2026-06-03T18:28:53+00:00

I’m playing arround with JSP and Servlets and have the following problem: I have

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I’m playing arround with JSP and Servlets and have the following problem:

I have a JSP which implements something like a small “Login-Function”. The code is the following:

<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
</head>
<body>

Enter username and password:<br />
<hr />

<form method="GET" name="login" action="LoginCheck">
username<br />
<input type="text" name="loginName" /><br />
Password<br />
<input type="password" name="password" /><br />
<input type="submit" value="login" />
<input type="reset" value="reset" />
</form>

</body>
</html>

As you can see i want to access the servlet LoginCheck. The code is the following:

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class LoginCheck extends HttpServlet {
    private static final long serialVersionUID = 1L;

    protected void doGet(HttpServletRequest request, HttpServletResponse response)     throws ServletException, IOException
    {
        response.setContentType("text/html");
        PrintWriter out = response.getWriter();

        String loginName = request.getParameter("loginName");
        String password = request.getParameter("password");

        if(loginName.equals("admin"))
        {
            if(password.equals("test"))
            {
                out.println("Username and password are correct!");
            }else
            {
                out.println("Password were are incorrect!<br />");
                out.println("<a href='index.jsp'>Here</a> you can get back to the Loginpage!");
            }
        }else
        {
            out.println("Username doesn't exist.<br />");
            out.println("<a href='index.jsp'>Here</a> you can get back to the Loginpage!");
        }
    }
}

If i use the code of the servlet in another JSP, everything works fine, but i am not able to access the servlet. The XML ist the following:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"     xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-    app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee     http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>Servlet</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>
</web-app>

The server is a Jetty Server and no, i’m not allowed tu use a Tomcat.
The structure of my Project in Eclipse looks like this:
http://imageshack.us/photo/my-images/204/eclipseo.png/

Can you tell me why i can’t access the servlet?

Thanks!

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1 Answer

  1. Editorial Team

    You need to declare the servlet and the servlet mapping on your web.xml:

    <servlet>
    <servlet-name>ServletName</servlet-name>
    <servlet-class>servlet.LoginCheck</servlet-class>
</servlet>

<servlet-mapping>
    <servlet-name>ServletName</servlet-name>
    <url-pattern>*</url-pattern>
</servlet-mapping>

    Also, If more than of your servlets share the common URL pattern, you must be careful about the order of their declaration in web.xml

    For example: If you have two servlets named servlet1 and servlet2 and you want to invoke servlet1 on /something/something2

    but mean while want to invoke servlet2 on /something/*

    than servlet1 should be declared before servlet2 in web.xml otherwise servlet2 will be invoked on every url pattern starting with /something/

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