Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8154353
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 6, 20262026-06-06T16:19:03+00:00 2026-06-06T16:19:03+00:00

I’m playing with Behat and Selenium server. I’m trying to target a specific tag

  • 0

I’m playing with Behat and Selenium server.
I’m trying to target a specific tag based on its position in the document.

I use AquaPath, a GUI to play with XPath and works fine.
My problem is that when i try the same expression in Behat/Selenium, i have a “The expression is not a legal expression” error message.

Here is my Xpath :

(//label)[5]/@for

I’m looking for the “for” attribute of the fifth label element having this attribute.
Seems easy, but doesn’t work and I really don’t know why…

Here is the complete log (note that //html is added automatically):

The given selector //html//(label)[1] is either invalid or does not result in a WebElement. The following error occurred:
[InvalidSelectorError] Unable to locate an element with the xpath expression //html//(label)[1] because of the following error:
[Exception... "The expression is not a legal expression."  code: "51" nsresult: "0x805b0033 (NS_ERROR_DOM_INVALID_EXPRESSION_ERR)"  location: "file:///var/folders/66/bv_nvdt97f33pm2qn78v_8qc0000gn/T/anonymous5419845357799771264webdriver-profile/extensions/fxdriver@googlecode.com/components/driver_component.js Line: 2621"]
Command duration or timeout: 6 milliseconds
For documentation on this error, please visit: http://seleniumhq.org/exceptions/invalid_selector_exception.html
Build info: version: '2.23.1', revision: '17143', time: '2012-06-08 18:59:04'
System info: os.name: 'Mac OS X', os.arch: 'x86_64', os.version: '10.7.4', java.version: '1.6.0_33'
Driver info: driver.version: EventFiringWebDriver
Session ID: c3bdf2e6-5042-ac4a-95c5-4735f4318899

Any idea ?

Here is the HTML (labels are not always at the same depth) :

<!DOCTYPE html>
<html>
  <head></head>
  <body>
    <form action="" method="get" accept-charset="utf-8">
      <label for="label1"></label>
      <label for="label2"></label>
      <div>
        <label for="label3"></label>        
      </div>
      <fieldset>
        <div>
          <label for="label4"></label>
        </div>        
      </fieldset>
      <label for="label5"></label>
      <label for="label6"></label>
      <label for="label7"></label>
      <label for="label8"></label>
      <label for="label9"></label>
      <p><input type="submit" value="Continue &rarr;"></p>
    </form>
  </body>
</html>
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-06T16:19:07+00:00Added an answer on June 6, 2026 at 4:19 pm

    My opinion is that “find()” method with “xpath” selector can’t get an attribute, only an element. Getting the attribute must be done via “getAttribute()”.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am trying to understand how to use SyndicationItem to display feed which is
I want use html5's new tag to play a wav file (currently only supported
I'm trying to select an H1 element which is the second-child in its group
I'm trying to use string.replace('’','') to replace the dreaded weird single-quote character: ’ (aka
link Im having trouble converting the html entites into html characters, (&# 8217;) i
Basically, what I'm trying to create is a page of div tags, each has
I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
In my XML file chapters tag has more chapter tag.i need to display chapters
I am trying to render a haml file in a javascript response like so:
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.