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Home/ Questions/Q 6659423
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:01:57+00:00 2026-05-26T02:01:57+00:00

I’m playing with static keyword. In the code below I can’t figure out why

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I’m playing with static keyword. In the code below I can’t figure out why x save it’s before state and increment.
I was expecting to print 1 tree times. As I know a such behaivor should happen if I declare x as static.

void print_it(void);

    int main (int argc,  const char * argv[])
    {
        print_it();
        print_it();
        print_it();
        exit(EXIT_SUCCESS);
    }

    void print_it(void)
    {
        int x;
        printf("%d\n", x++);
    }
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  1. Editorial Team
    Editorial Team
    2026-05-26T02:01:58+00:00Added an answer on May 26, 2026 at 2:01 am

    You have not initialized x to any value. Therefore, the initial value in x would be garbage and as it happens, this garbage increments itself every time because it is probably using the same memory location everytime.

    Try changing your code to this:

    void print_it(void);
    int main (int argc,  const char * argv[])
    {
        print_it();
        print_it();
        print_it();
        exit(EXIT_SUCCESS);
    }
    
    void print_it(void)
    {
        int x = 0;
        printf("%d\n", x++);
    }
    
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