Home/ Questions/Q 6551495
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-25T12:20:42+00:00

I’m pretty new to Django’s template system- Basically, I’m trying to print out all

  • 0

I’m pretty new to Django’s template system-
Basically, I’m trying to print out all the contents of a list that I’m passing to django in a context.

The relevant part of my urls.py is here-

 url(r'^class/$', twobooks.classes.views.getAllInformation, {'template_name':'classes/displayBooks.html'}),

Now, in my views getAllInformation is as follows-

def getAllInformation(searchTerm,template_name):
    nameAndNumberStore = modifySearchTerm(searchTerm)
    url = modifyUrl(nameAndNumberStore)
    soup = getHtml(url)
    information = []
    if (checkIfValidClass(soup,nameAndNumberStore)):
        storeOfEditions = getEdition(soup)
        storeOfAuthorNames = getAuthorName(soup)
        storeOfBookNames = getBookNames(soup)
        storeOfImages = getImages(soup)
    information.append(storeOfAuthorNames)#REMEMBER this is a list of two lists 
    information.append(storeOfEditions)
    return render_to_response(
    template_name,
    {'authors': storeOfAuthorNames},
    )

and displayBooks.html is as follows-

<html>
<head>
<body>
<h1>Testing the class page backend</h1>
<ul>
{ % for author in authors|safe% }
    <li>{{ author }}</li>
{ % endfor % }
</ul>

</body> 

</html>

I think this is fairly simple, but I’m not sure what’s going on, so thought I’d ask for some help – thanks!

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Applying the safe filter will turn anything into a string. If you start with the literal [1, 2, 'foo', u'bar'], you’re going to end up with approximately the literal u"[1, 2, 'foo', u'bar']" (or something like it—I’m not quite certain of how it’s rendered as I’ve never tried doing it; also I say “approximately” as it’s actually a SafeString instance not a unicode instance). Then, iteration is going over each character in the produced string, which isn’t what you want.

    Instead, you can use the safeseq filter which applies the safe filter to each element in the sequence, 

    <ul>
{% for author in authors|safeseq %}
    <li>{{ author }}</li>
{% endfor %}
</ul>

    Or, you could apply safe to the value inside the iterator.

    <ul>
{% for author in authors %}
    <li>{{ author|safe }}</li>
{% endfor %}
</ul>

    I would recommend safeseq, as you may then be able to optimise the template further, if you wish, with the unordered_list filter, if you only wish to display the values. (Note that I’m not certain of how it behaves—it’s possible that this would unmark it as safe. You’d need to try it.)

    <ul>{{ authors|safeseq|unordered_list }}</ul>
    • 0