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Home/ Questions/Q 4272388
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T07:34:15+00:00 2026-05-21T07:34:15+00:00

I’m pretty new to hashing in Java and I’ve been getting stuck on a

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I’m pretty new to hashing in Java and I’ve been getting stuck on a few parts. I have a list of 400 items (and stored in a list of 1.5x = 600), which the item id’s range from 1-10k. I’ve been looking at a few hash functions and I initially copied the examples in the packet, which just used folding. I noticed that I’ve been getting about 50-60% null nodes, which is apparently too many. I also noticed that just modding the id by 600 tends to reduce it to a solid 50% nulls.

My current hash function looks something like, and for being as ugly as it is, it’s only a 1% decrease in nulls from a simple modding, with an avg list length of 1.32…

   public int getHash( int id )
   {
      int hash = id;

      hash <<= id % 3;
      hash += id << hash % 5;

      /* let's go digit by digit! */          
      int digit;
      for( digit = id % 10;
           id != 0;
           digit = id % 10, id /= 10 )
      {
         if ( digit == 0 ) /* prevent division by zero */
            continue;
         hash += digit * 2;
      }

      hash >>= 5;
      return (hash % 600);
   }

What are some good techniques for creating simple hash functions?

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  1. Editorial Team
    Editorial Team
    2026-05-21T07:34:16+00:00Added an answer on May 21, 2026 at 7:34 am

    I would keep it simple. Return the id of your element as your hashcode, and let the hashtable worry about rehashing it if it feels it needs to. Your goal should be to make a hash code unique to your object.

    The Java HashMap uses the following rehashing method:

    /**
     * Applies a supplemental hash function to a given hashCode, which
     * defends against poor quality hash functions.  This is critical
     * because HashMap uses power-of-two length hash tables, that
     * otherwise encounter collisions for hashCodes that do not differ
     * in lower bits. Note: Null keys always map to hash 0, thus index 0.
     */
    static int hash(int h) {
        // This function ensures that hashCodes that differ only by
        // constant multiples at each bit position have a bounded
        // number of collisions (approximately 8 at default load factor).
        h ^= (h >>> 20) ^ (h >>> 12);
        return h ^ (h >>> 7) ^ (h >>> 4);
    }
    
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