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Home/ Questions/Q 7795871
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T23:11:47+00:00 2026-06-01T23:11:47+00:00

I’m pretty new to writing Android apps, and I wanted to write a piece

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I’m pretty new to writing Android apps, and I wanted to write a piece of code that broadcasts the sensor data at a regular interval, say 1 second. Searching open-source codes I managed to write a sender class as below:

public class Sender extends Thread {
    private static final String TAG = "Sending";
    private static final int PORT = 12346;
    private static final int TIMEOUT_MS = 500;
    private static final int BUF_SIZE = 1024;
    private WifiManager mWifi;

    Sender(WifiManager wifi) {
        mWifi = wifi;
    }

    public void run() {
        try {
            DatagramSocket socket = new DatagramSocket(PORT);
            socket.setBroadcast(true);
            socket.setSoTimeout(TIMEOUT_MS);
            sendData(socket);
            socket.close();
            Thread.sleep(1000);
        }
        catch (IOException ioe) {
            Log.e(TAG, "Couldn't send data", ioe);
        } 
        catch (InterruptedException ie) {
            Log.e(TAG,  "Can't sleep", ie);
        }
    }

    private void sendData(DatagramSocket socket) throws IOException {
        byte[] buf = new byte[BUF_SIZE];
        buf = object.toString().getBytes();
        InetAddress addr = InetAddress.getByName("192.168.0.255"); // TO FIX
        DatagramPacket packet = new DatagramPacket(buf, buf.length, addr, PORT);
        socket.send(packet);
    }

    public void main(String[] args) {
        new Sender(null).start();
        while (true) {
        }
    }
}

And here’s how I start it from within the onCreate method:

public void onCreate(Bundle savedInstanceState) {
...

    new Sender((WifiManager) getSystemService(Context.WIFI_SERVICE)).start();
...
}

Now, if I open Wireshark on my laptop, I only see one packet sent at the time the app is started instead of every one second.

Could someone please point out where I did wrong? Honestly I’m not that familiar with threads and stuff, so I may just be missing something obvious here…

EDIT

OK, so the run method must be looped. See corrected code in the answer below.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T23:11:48+00:00Added an answer on June 1, 2026 at 11:11 pm

    Here’s the corrected run method code:

    public void run() {
                while (true) {
                    try {
                        DatagramSocket socket = new DatagramSocket(PORT);
                        socket.setBroadcast(true);
                        socket.setSoTimeout(TIMEOUT_MS);
                        sendData(socket);
                        socket.close();
                        Thread.sleep(1000);
                    }
                    catch (IOException ioe) {
                        Log.e(TAG, "Couldn't send data", ioe);
                    } 
                    catch (InterruptedException ie) {
                        Log.e(TAG,  "Can't sleep", ie);
                    }
                }
    }
    
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