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Home/ Questions/Q 6082683
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T11:19:01+00:00 2026-05-23T11:19:01+00:00

I’m pretty sure that there’s such question.. Here’s the issue – I want to

  • 0

I’m pretty sure that there’s such question..

Here’s the issue – I want to split a string, using some specified chars as delimiters, but I also want the substrings to have length, close to the specified.


Real world example – split long subtitles lines.

Example:

1234,asd dsa qwerty 567,

I want to split the line to a number of lines with max length, let’s say 10, but I don’t want to “split” words. So, this should become:

1234,asd
dsa qwerty 
567, 

Of course, I can split the lines by delimiters and then concatenate them again, till I reach the desired length, but this will be terribly slow.

I thought about using str.find (and use the returned position) but it can’t work with regex (because of the different delimiters – ., ,, ;, \n, , etc.).

I think about re.findall, but I can’t think of an regex. I thought something about something like

(.*){, max_len}\s

with re.S, but it’s obviously not working. There should be some tricky way..

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  1. Editorial Team
    Editorial Team
    2026-05-23T11:19:02+00:00Added an answer on May 23, 2026 at 11:19 am

    The following code splits your string as desired at spaces with a width of 10:

    import re
    r = "1234,asd dsa qwerty 567,"
    p = re.compile("(.{,10})($|\s)")
    r = p.sub("\\1\n", r)
    

    In this case it produces output

    1234,asd
    dsa qwerty
    567,
    

    when split with width 5 you get

    1234,asd
    dsa
    qwerty
    567,
    

    You can see, that words are never split with this method.

    If you like other delimiters just replace “\s” with the desired regular expression.

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