I’m profiling (SQL Server 2008) some of our views and queries to determine their efficiency with regards to CPU usage and Reads. I understand Reads are the number of logical disk reads in 8KB pages. But I’m having a hard time determining what I should be satisfied with.
For example, when I query one of our views, which in turn joins with another view and has three OUTER APPLYs with table-valued UDFs, I get a Reads value of 321 with a CPU value of 0. My first thought is that I should be happy with this. But how do I evaluate the value of 321? This tells me 2,654,208 bytes of data were logically read to satisfy the query (which returned a single row and 30 columns).
How would some of you go about determining if this is good enough, or requires more fine tuning? What criteria would you use?
Also, I’m curious what is included in the 2,654,208 bytes of logical data read. Does this include all the data contained in the 30 columns in the single row returned?
The 2.5MB includes all data in the 321 pages, including the other rows in the same pages as those retrieved for your query, as well as the index pages retrieved to find your data. Note that these are logical reads, not physical reads, e.g. read from a cached page will make the read much ‘cheaper’ – take CPU and profiler cost indicator as well when optimising.
w.r.t. How to determine an optimum ‘target’ for reads.
FWIW I compare the actual reads with a optimum value which I can think of as the minimum number of pages needed to return the data in your query in a ‘perfect’ world.
e.g. if you calculate roughly 5 rows per page from table x, and your query returns 20 rows, the ‘perfect’ number of reads would be 4, plus some overhead of navigating indexes (assuming of course that the rows are clustered ‘perfectly’ for your query) – so utopia would be around say 5-10 pages.
For a performance critical query, you can use the actual reads vs ‘utopian’ reads to micro-optimise, e.g.:
You might find this article useful
HTH!