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Home/ Questions/Q 8757115
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T14:13:40+00:00 2026-06-13T14:13:40+00:00

I’m querying an SDO_GEOMETRY field to return a given point in a shape, and

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I’m querying an SDO_GEOMETRY field to return a given point in a shape, and I would like to get the GPS coordinates for that point. My query is as follows:

select 
sdo_lrs.locate_pt(sdo_lrs.convert_to_lrs_geom(shape),0.02).sdo_ordinates  
from 
TEST_SCHEMA.TEST_TABLE
where 
route='ABC'
and
segmentnum='101.1'

This returns an SDO_ORDINATE_ARRAY like so:

MDSYS.SDO_ORDINATE_ARRAY(100000.203621556,999999.57084293,0.02)

How do I convert the first two elements of the SDO_ORDINATE_ARRAY into GPS coordinates? I haven’t been able to find anything in the Oracle Spatial documentation related to a function that would accomplish this.

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  1. Editorial Team
    Editorial Team
    2026-06-13T14:13:41+00:00Added an answer on June 13, 2026 at 2:13 pm

    It turns out you have to transform the coordinate system of the shape before it’s passed to convert_to_lrs_geom(), using sdo_cs.transform(). In this case the SRID is 8307 (thanks to jim mcnamara for pointing out that the SRID was the issue), so the SQL to return the correct coordinates is:

    select 
    sdo_lrs.locate_pt(sdo_lrs.convert_to_lrs_geom(sdo_cs.transform(shape,8307)),0.02).sdo_ordinates  
    from 
    TEST_SCHEMA.TEST_TABLE
    where 
    route='ABC'
    and
    segmentnum='101.1'
    
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