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Home/ Questions/Q 8716371
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T06:03:50+00:00 2026-06-13T06:03:50+00:00

I’m quite new to C# and currently developing an application using the EntityFramework. I

  • 0

I’m quite new to C# and currently developing an application using the EntityFramework. I would like to extend the functionality of the database context class, so that I can call a method getPool() so that it hands out the according DbSet member of the class.

I need to implement it as a template as it will be later called from other templates, which are just knowing about the (global) database context object and a type T (having a given superclass) for which they shall query the database.

Here is what I tried (a bit simplified – original example is too complicated):

public class TestContext : DbContext
{
    public DbSet<TestA> ATests { get; set; }
    public DbSet<TestB> BTests { get; set; }

    public IQueryable<T> getPool<T>() where T : TestA {
       return (IQueryable<T>)ATests;
    }
    public IQueryable<T> getPool<T>() where T : TestB {
       return (IQueryable<T>)BTests;
    }
}

The error message is

Error: Type ‘…’ already defines a member called ‘…’ with the same parameter types.

And it occurs at the line of the second specialized definition of my template (public IQueryable<T> getPool<T>() where T : TestB).

The question is: How to fix this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T06:03:51+00:00Added an answer on June 13, 2026 at 6:03 am

    Unfortunately, in C#, you cannot overload a method by using a generic type constraint like this. You will have to give them different names like this

    public class TestContext : DbContext
    {
        public DbSet<TestA> ATests { get; set; }
        public DbSet<TestB> BTests { get; set; }
    
        public IQueryable<T> getPoolA<T>() where T : TestA {
           return (IQueryable<T>)ATests;
        }
        public IQueryable<T> getPoolB<T>() where T : TestB {
           return (IQueryable<T>)BTests;
        }
    }
    

    Another solution would be to do something like this:

    public class TestContext : DbContext
    {
        public DbSet<TestA> ATests { get; set; }
        public DbSet<TestB> BTests { get; set; }
    
        public IQueryable<T> getPool<T>() {
           return (typeof(T) == typeof(TestA))
                      ? (IQueryable<T>)ATests
                      : (IQueryable<T>)BTests;
        }
    }
    

    Now, you can make this even cleaner, since IQueryable<T> is covariant in T, you can avoid casting:

    public class TestContext : DbContext
    {
        public DbSet<TestA> ATests { get; set; }
        public DbSet<TestB> BTests { get; set; }
    
        public IQueryable<T> getPool<T>() {
           return (typeof(T) == typeof(TestA)) ? ATests : BTests;
        }
    }
    

    If you want to avoid testing for types you can do something like this:

    public class TestContext : DbContext
    {
        readonly Dictionary<Type, object> _sets;
    
        public DbSet<TestA> ATests { get; set; }
        public DbSet<TestB> BTests { get; set; }
    
        public TestContext()
        {
            _sets = new Dictionary<Type, object>
            {
                { typeof(TestA), ATests },
                { typeof(TestB), BTests }
            }
        }
    
        public IQueryable<T> getPool<T>() {
           return (IQueryable<T>)_sets[typeof(T)];
        }
    }
    
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