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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T07:43:44+00:00 2026-05-15T07:43:44+00:00

I’m quite new to Java and having an issue checking null element in integer

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I’m quite new to Java and having an issue checking null element in integer array.
I’m using Eclipse for editor and the line that checks null element is showing error:

Line that complains:

if(a[i] != null) {

Error msg from Eclipse:

The operator != is undefined for the argument type(s) int, null

In PHP, this works without any problem but in Java it seems like I have to change the array type from integer to Object to make the line not complain (like below)

Object[] a = new Object[3];

So my question is if I still want to declare as integer array and still want to check null,
what is the syntax for it?

Code:

public void test() {
        int[] a = new int[3];
        for(int i=0; i<a.length; i++) {
            if(a[i] != null) { //this line complains...
                System.out.println('null!');
            }
        }
    }
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  1. Editorial Team
    Editorial Team
    2026-05-15T07:43:45+00:00Added an answer on May 15, 2026 at 7:43 am

    In Java, an int is a primitive type and cannot be null. Objects, however, are stored as references, so if you declare an object reference but do not make a new object, the reference will be null.

    Integers are object wrappers around ints, meaning they can be null.

    public void test() {
            Integer[] a = new Integer[3];
            for(int i=0; i<a.length; i++) {
                if(a[i] != null) { //should now compile
                    System.out.println('null!');
                }
            }
        }
    
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