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Home/ Questions/Q 8613819
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T04:58:25+00:00 2026-06-12T04:58:25+00:00

I’m quite new to webdevelopment and AJAX and I’m facing a little issue there.

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I’m quite new to webdevelopment and AJAX and I’m facing a little issue there. Basically, I have a form on my webpage. When I submit this form, it makes an AJAX call to my controller, send me the data I want back, and change the html content of the page.

JS code :

$(document).ready(function() {

    $("#mydiv table tbody td").click(function() {
        alert("You clicked my <td>!" + $(this).html() + 
              "My TR is:" + $(this).parent("tr").html());
    });



    $('#myform').submit(function()
    {
        try {
            var host = $("#host").val();
            var port = $("#port").val();
            var username = $("#username").val();
            var password = $("#password").val();
            var database = $("#database").val();

            $.ajax({
                type: "POST",
                url: "/management/connectDatabase",
                dataType: "JSON",
                data: "host="+host+"&port="+port+"&username="+username+"&password="+password+"&database="+database,
                cache: false,
                success: 
                    function(data){
                        $('#mydiv').html(show_tables(data));
                    },
            });
            return false;
        }

        catch(e){
            console.debug(e);
        }
    });
});

function show_tables(data)
{
    var html = '<div id="mydiv">';

    html += '<table class="display" id="example">';
    html += '<thead><tr><th>Tables</th></tr></thead><tbody>';
    for (var tablesCount = 0; tablesCount < data.tables.length; tablesCount++){
        html += '<tr class=gradeA id="trtest">';
        html += '<td id="tdtest">' + data.tables[tablesCount] + '</td>';
        html += '</tr>';
    }
    html += '</tbody></table>';

    html += '</div>';
    return html;
}

When I submit the form, the HTML is generating right, and I can see my content. But, I can’t click on any entries of the <table>. Moreover, when I want to see the sourcecode of my page, it doesn’t displays me the table, but still my form, even if it has still been validated.

Could someone explain me what I do wrong here ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T04:58:26+00:00Added an answer on June 12, 2026 at 4:58 am

    Depending on which jQuery version you’re using, you need to either bind the click event using jQuery.delegate or jQuery.on in order for things to work with dynamically added DOM elements.

    Edit: as pointed out by Geert Jaminon, you have to use the selector parameter of the on function. This works for me.

    $("#mydiv table tbody").on('click', 'td', function() {
        alert("You clicked my <td>!" + $(this).html() + 
              "My TR is:" + $(this).parent("tr").html());
    });
    
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