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Home/ Questions/Q 6005343
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T01:23:03+00:00 2026-05-23T01:23:03+00:00

I’m reading a book about data structures in java, and it’s talking about iterators

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I’m reading a book about data structures in java, and it’s talking about iterators now. I saw the following code and it seems odd to me. In the following code, AbstractIterator is an abstract class that implements Iterator<E>, UniqueFilteris a subclass of AbstractIterator that is not abstract, and data is a Vector. I guess I don’t understand how in the first line you can take the output of the Vector.iterator() method and cast that into an abstract class. After line 1, is dataIterator not an instantiated instance of an abstract class?

AbstractIterator<String> dataIterator =
    (AbstractIterator<String>)data.iterator();
AbstractIterator<String> ui = new UniqueFilter(dataIterator);
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  1. Editorial Team
    Editorial Team
    2026-05-23T01:23:04+00:00Added an answer on May 23, 2026 at 1:23 am

    The problem is that there are two different types we are talking about. The (run time) type of an object and the (compile time) type of a reference.

    1. dataIterator is a reference of an abstract type – that’s ok.
    2. data.iterator() returns a reference to an object whose type is not clear from the example, but apparently it’s a concrete type which inherits from AbstractIterator<String> – that’s ok
    3. You can always assign a reference to object of type B to a reference to object of type A if B is a child of A, even if A is abstract (or interface). You actually don’t need the cast.

    So after line one dataIterator is still a reference of type AbstractIterator<String>, but it’s a reference to an object of a concrete type which implements AbstractIterator<String>.

    Remember, in JAVA all the object variables are actually references.

    UniqueFilter is irrelevant for this question, btw.

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