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Home/ Questions/Q 7194745
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T20:26:07+00:00 2026-05-28T20:26:07+00:00

I’m reading a tutorial on Perlin Noise , and I came across this function:

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I’m reading a tutorial on Perlin Noise, and I came across this function:

function IntNoise(32-bit integer: x)             

    x = (x<<13) ^ x;
    return ( 1.0 - ( (x * (x * x * 15731 + 789221) + 1376312589) & 7fffffff) / 1073741824.0);    

end IntNoise function

While I do understand some parts of it, I really don’t get what are (x<<13) and & 7fffffff supposed to mean (I see that it is a hex number, but what does it do?). Can someone help me translate this into JS? Also, normal integers are 32 bit in JS, on 32 bit computers, right?

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  1. Editorial Team
    Editorial Team
    2026-05-28T20:26:09+00:00Added an answer on May 28, 2026 at 8:26 pm

    It should work in JavaScript with minimal modifications:

    function IntNoise(x) {
        x = (x << 13) ^ x;
        return (1 - ((x * (x * x * 15731 + 789221) + 1376312589) & 0x7fffffff) / 1073741824);
    }
    

    The << operator is a bitwise left-shift, so << 13 means shift the number 13 bits to the left.

    The & operator is a bitwise AND. Doing & 0x7fffffff on a signed 32-bit integer masks out the sign bit, ensuring that the result is always a positive number (or zero).

    The way that JavaScript deals with numbers is a bit quirky, to say the least. All numbers are usually represented as IEEE-754 doubles, but… once you start using bitwise operators on a number then JavaScript will treat the operands as signed 32-bit integers for the duration of that calculation.

    Here’s a good explanation of how JavaScript deals with bitwise operations:

    • Bitwise Operators
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