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Home/ Questions/Q 6801659
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:07:36+00:00 2026-05-26T19:07:36+00:00

I’m reading and store a RSS feed in my database.I’m using this code <?php

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I’m reading and store a RSS feed in my database.I’m using this code

    <?php
      include_once 'db.php';
       $homepage = file_get_contents('http://rss.cnn.com/rss/edition_us.rss');

         $movies = new SimpleXMLElement($homepage);
          foreach($movies->channel->item as $opt){
            $title= $opt->title;
        $tittle=mysql_real_escape_string($title);
           $link=$opt->link;
           $links=mysql_real_escape_string($link);
           $des=$opt->description;
            $dess=mysql_real_escape_string($des);

           $sql="INSERT INTO store_feed (title, link, description)
             VALUES ('$tittle','$links','$dess')";

            $result=mysql_query($sql) or die('Error, insert query failed');
             }


              ?>

and table structure is

Table structure for table store_feed

 CREATE TABLE IF NOT EXISTS `store_feed` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `title` varchar(200) NOT NULL,
    `link` varchar(200) NOT NULL,
      `description` varchar(500) NOT NULL,
     `feedburner` varchar(200) NOT NULL,
     PRIMARY KEY (`id`)
       ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

now my requirement is when insert a new record if link is same then update only title and description of this field without insert record again.
in other word I want to stop duplicate data if link is same.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:07:37+00:00Added an answer on May 26, 2026 at 7:07 pm

    Usually, I do something like this:

    WARNING: UNTESTED CODE!

    $sql = "SELECT id FROM store_feed WHERE link = '$links' LIMIT 1";
    $rs = mysql_query($sql) or die( mysql_error() );
    if( mysql_num_rows($rs) > 0)//we got link
    {
        $r = mysql_fetch_array($rs);
        $id = $r['id'];
        $sql = "UPDATE store_feed SET title = '$title', description = '$dess' WHERE id = '$id'";
        mysql_query($sql) or die( mysql_error() );
    } else {
        $sql = "INSERT INTO store_feed (title, link, description) VALUES ('$tittle','$links','$dess')";
        mysql_query($sql) or die( mysql_error() );
    }
    
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