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Home/ Questions/Q 7803161
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T01:29:05+00:00 2026-06-02T01:29:05+00:00

I’m reading chapter 16 so that I may begin my assignments for my C++

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I’m reading chapter 16 so that I may begin my assignments for my C++ class. This section is on exception handling. I understand the concept behind a try / catch construct, however, one of the examples in the book is a bit confusing to me. I’m hoping for some explanation as to how this is working. The sample code is below:

// Includes, header guards, and namespace std...
class IntRange
{
 private:
  int intput;
  int lower;
  int upper;

 public: 
  // Exception class
  class OutOfRange { }; // This is exactly how it appears in the text.

  IntRange(int low, int high) { lower = low; upper = high; }
  int GetInput()
  {
    cin >> input;
    if (input < lower || input > upper)
      throw OutOfRange(); // <-- This is my question in particular. What is this?
    return input;
  }
};

// End header guard.

// Program entry point.

int main()
{
  IntRange range(5, 10)
  int userValue;

  cout << "Enter a value in the range 5 - 10: ";
  try
  {
    userValue = range.getInput();
    cout << "You entered " << userValue << endl;
  }
  catch (IntRange::OutOfRange) // <-- Again, what is this delcaration and how can
                               // this data type be defined when IntRange does not
                               // have a default constructor?
  {
    cout << "That value is out of range.\n";
  }

  return 0;
}

The code is exactly as it appears in the textbook, except I put some stuff on the same line in order to keep the question from becomming really long.

If you notice any errors, it’s most likely a typo, but the most important points have been double-checked.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T01:29:07+00:00Added an answer on June 2, 2026 at 1:29 am
      throw OutOfRange(); // <-- This is my question in particular. What is this?
    

    This default constructs an object of OutOfRange then throws it.
    Even if you do not define a methods in a class the compiler will automatically generate a couple for you one of these is the default constructor. Thus even if you don’t specify a constructor there will be one there (Do a google on rule 3/5 for explanation of what methods are generated by the compiler).

    catch (IntRange::OutOfRange) // <-- Again, what is this delcaration and how can
                                 // this data type be defined when IntRange does not
                                 // have a default constructor?
    

    Here we are catching an object of type IntRange::OutOfRange. Note: we are not catching an object of IntRange. We are catching the class OutOfRange that happens to be defined inside the class IntRange (apart from where it is defined there is no other relationship).

    Also note: Unless you disable it the compiler will automatically generate a copy constructor for all classes. Thus exceptions are usually copy constructed from the throw point to the catch point (its a tiny bit more complex). So your exception object must be copyable.

    Also note it is best to catch exceptions by const reference:

    catch (IntRange::OutOfRange const& e)
    

    The avoids problems associated with slicing objects that are part of exception hierarchies.

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