Question

I’m reading host information from a text file and pass it to an ssh command:
The text file contains the host, user and password for the ssh command

while read LINE
do
    R_USER=$(echo $LINE | cut -d ',' -f 1)                  
    R_HOST=$(echo $LINE | cut -d ',' -f 2)                                  
    PY_SCRIPT=$(echo $LINE | cut -d ',' -f 4)               

    ssh $R_USER@$R_HOST 'touch /home/user/file_name.txt'

done </path_name/file_name

As it turns out the while loop is only executed once even if the host text file contains multiple host information.
When I remove the ssh command the while loop gets executed as much as there are lines in the host information text file.

Not sure why this is so.
Any information on this?

Roland

Answer 1

The default standard input handling of ssh drains the remaining line from the while loop.

To avoid this problem, alter where the problematic command reads standard input from. If no standard input need be passed to the command, read standard input from the special /dev/null device:

while read LINE
  do
    R_USER=$(echo $LINE | cut -d ',' -f 1)                  
    R_HOST=$(echo $LINE | cut -d ',' -f 2)                                  
    PY_SCRIPT=$(echo $LINE | cut -d ',' -f 4)               

    ssh $R_USER@$R_HOST 'touch /home/user/file_name.txt' < /dev/null

done </path_name/file_name

Or alternatively, try using ssh -n which will prevent ssh from reading from standard input. For instance:

ssh -n $R_USER@$R_HOST 'touch /home/user/file_name.txt'