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Home/ Questions/Q 8544561
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T12:35:24+00:00 2026-06-11T12:35:24+00:00

I’m reading the book Java Concurrency in Practice. In section 3.2 it talks about

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I’m reading the book Java Concurrency in Practice. In section 3.2 it talks about escaping outer class while publishing inner classes. Now I’m looking for the syntax that makes it possible. Let’s say we have:

public class ThisEscape {

    public Integer i = 47;

    public ThisEscape(EventSource source) {
        source.registerListener(
            new EventListener() {
                public void onEvent(Event e) {
                    doSomething(e);
                }
        });
    }
}

If I got it right about escaping outer class, I assume that EventSource somehow can access EventListener enclosing class (in this case ThisEscape). Say we implement EventSource as the following:

public class EventSource {

    public void registerListener(EventListener listener) {
        // How does it have access to enclosing class of the listener variable i?
    }

}

Just how can we have access to the public variable i from registerListener?


Just found a typo. Replaced “EventSource enclosing class” with “EventListener enclosing class”. Fortunately everybody got the right version.

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  1. Editorial Team
    Editorial Team
    2026-06-11T12:35:25+00:00Added an answer on June 11, 2026 at 12:35 pm

    Imagine EventSource is written something like this:

    public class EventSource {
        public void registerListener(EventListener listener) {
            listener.onEvent(null);
        }
    }
    

    For the purposes of the memory model it doesn’t matter that it doesn’t have direct access to the ThisEscape object. (It might – reflection, some method on EventListener, in the same package, enabled by some method in the same package, etc.) What matters is that the fields of ThisEscape are being accessed in some manner, which will likely be thread-unsafe.

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