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Home/ Questions/Q 8547569
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T13:17:39+00:00 2026-06-11T13:17:39+00:00

I’m reading the docs for java.util.HashMap , and it says: If multiple threads access

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I’m reading the docs for java.util.HashMap, and it says:

If multiple threads access this map concurrently, and at least one of
the threads modifies the map structurally, it must be synchronized
externally.

What does “it” mean? “it” could be interpreted to mean the thread that modifies the map, or it could mean the map itself.

Both the “safe for multiple threads reading” and “safe only on single thread when there is a writer” cases are no brainers (at least to me), which makes me believe that calling the “multiple readers and single writer” case speciffically in the documentation means the statement should be interpreted as “safe to have multiple threads reading and a single thread writing”, rather than the no brainer “lock everything when you have a writer”.

More so, the hashtable implementation in .Net is (unambiguously) documented as:

Hashtable is thread safe for use by multiple reader threads and a single writing thread

(the .Net classes are not thread safe by default), so there must be something to the “multiple reader threads and one single writer thread” case.

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  1. Editorial Team
    Editorial Team
    2026-06-11T13:17:40+00:00Added an answer on June 11, 2026 at 1:17 pm

    The internal elements are in an indeterminate state when a thread “modifies the map structurally” so reads could be affected. Thus the requirement to use some method external to the map to synchronize both reads and writes.

    Perhaps the writers of the .Net library were more careful to keep their internal structure in a determinate state during updates.

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