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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:12:24+00:00 2026-05-26T23:12:24+00:00

I’m reading through: The C++ Standard Library: A Tutorial and Reference by Nicolai M.

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I’m reading through:

“The C++ Standard Library: A Tutorial and Reference by Nicolai M.
Josuttis”

and I’m in the section about Sets & Multisets. I came across a line regarding Inserting and Removing elements:

“Inserting and removing happens faster if, when working with multiple
elements, you use a single call for all elements rather than multiple
calls.”

I’m far from a data structures master, but I’m aware that they’re implemented with red-black trees. What I don’t understand from that is how would the STL implementers write an algorithm to insert multiple elements at once in a faster manner?

Can anyone shed some light on why this quote is true for me?

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  1. Editorial Team
    Editorial Team
    2026-05-26T23:12:25+00:00Added an answer on May 26, 2026 at 11:12 pm

    My first thought was that it might rebalance the tree only after inserting/erasing the whole range. Since the whole operation is inlined in practice, that seems more likely than the number of function calls.

    Checking the GCC headers on my local machine, this doesn’t seem to be the case – and anyway, I don’t know how the tradeoff between reduced rebalancing activity, and potentially increased search times for intermediate inserts to an unbalanced tree, would work out.

    Maybe it’s considered a QoI issue, but in any case, using the most expressive method is probably best, not just because it saves you writing a for loop and shows your intention most clearly, but because it leaves library writers latitude to optimise more aggressively in the future, without you needing to know and change your code.

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