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Home/ Questions/Q 6629153
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T22:13:10+00:00 2026-05-25T22:13:10+00:00

I’m reading through the dragon book and trying to solve an exercise that is

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I’m reading through the dragon book and trying to solve an exercise that is stated as follows

Write regular definitions for the following languages:

  • All strings of digits with no repeated digits. Hint: Try this problem first with a few digits, such as { 0, 1, 2 }.

Despite having tried to solve it for hours, I can’t imagine a solution, beside the extremely wordy

d0 -> 0?
d1 -> 1?
d2 -> 2?
d3 -> 3?
d4 -> 4?
d5 -> 5?
d6 -> 6?
d7 -> 7?
d8 -> 8?
d9 -> 9?
d10 -> d0d1d2d3d4d5d6d7d8d9 | d0d1d2d3d4d5d6d7d9d8 | ...

Hence having to write 10! alternatives in d10. Since we shall write this regular definition, I doubt that this is a proper solution. Can you help me please?

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  1. Editorial Team
    Editorial Team
    2026-05-25T22:13:11+00:00Added an answer on May 25, 2026 at 10:13 pm

    So the question didn’t necessarily ask you to write a regular expression, it asked you to provide a regular definition, which I interpret to include NFA’s. It turns out it doesn’t matter which you use, as all NFA’s can be shown to be mathematically equivalent to regular expressions.

    Using the digits 0, 1, and 2, a valid NFA would be the following (sorry for the crummy diagram):

    enter image description here

    Each state represents the last digit scanned in the input, and there are no loops on any of the nodes, therefore this is an accurate representation of a string with no repeated digits from the set {0,1,2}. Extending this is trivial (although it requires a large whiteboard 🙂 ).

    NOTE: I am making the assumption that the string “0102” IS valid, but the string “0012” is not.

    This can be converted to a regular expression (although it will be painful) by using the algorithm described here.

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