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Home/ Questions/Q 7763403
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T14:39:00+00:00 2026-06-01T14:39:00+00:00

I’m really a starter with Scala, so pardon me if I’m stupid here! I’m

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I’m really a starter with Scala, so pardon me if I’m stupid here!

I’m using play2.0/Scala for an assignment.

I want to populate a dropdown with distinct values(timesheetId here) and labels(a concat of 2 date values). So I did this.

@select(effortForm("timesheetId"),options(timesheets.map(aTimesheet=> aTimesheet.timesheetId.toString -> (aTimesheet.fromDate + " to " + aTimesheet.toDate))),'_label->"Choose Timesheet (*)")

But the page has a dropdown populated with same value (as a tuple) and label for options under select.

Overloaded method value [apply] cannot be applied to (List[(java.lang.String, java.lang.String)])

I want to see this as result

<option value="1">Sun Apr 08 18:23:32 PDT 2012 to Sun Apr 08 18:23:32 PDT 2012</option>

Please help!

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  1. Editorial Team
    Editorial Team
    2026-06-01T14:39:02+00:00Added an answer on June 1, 2026 at 2:39 pm

    Try this:

    @select(
      effortForm("timesheetId"),
      timesheets.map{ t =>
        t.timesheetId.toString -> (t.fromDate + " to " + t.toDate)
      },
      '_label- > "Choose Timesheet (*)"
    )
    

    Looking at the implementation of select, it looks like the second parameter should be a Seq[(String, String)] which would already be the case for your timesheets.map{ }.

    options(...) provides conveniences methods to constructs the Seq[(String, String)] and there is not a method that applies here.

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