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Home/ Questions/Q 337649
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T10:21:20+00:00 2026-05-12T10:21:20+00:00

I’m really new to PHP but what I want to do is make a

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I’m really new to PHP but what I want to do is make a dynamic table of contents for some of my companies job offerings.

So if i put all the pdfs of the job descriptions in a folder called ../jobops with the php file located in root directory what would I need to do.

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  1. Editorial Team
    Editorial Team
    2026-05-12T10:21:20+00:00Added an answer on May 12, 2026 at 10:21 am
    <?php
      $directory = "/jobops";
      $contents = scandir($directory);
        if ($contents) {
           foreach($contents as $key => $value) {
                 if ($value == "." || $value == "..") {
                    unset($key);
                 }
           }
        }
            echo "<ul>";
        foreach($contents as $k => $v) {
          echo "<li><a href=\"$directory/" . $v . "\">link text</a></li>";
        }
            echo "</ul>";
    
    ?>
    

    Should work. Takes the directory, scans it, maps all the filenames into an array $contents removes the relative urls (the “.” and “..”) and then echoes them out.

    Remember that foreach is relatively expensive, though; so you may wish to simply unset $contents[0] and $contents[1].


    Edited in response to the following (from the OP):

    Warning:
    scandir(www.markonsolutions.com/jobops)
    [function.scandir]: failed to open
    dir: No such file or directory in
    /home/content/t/i/m/timhish/html/test.php
    on line 5 Warning: scandir()
    [function.scandir]: (errno 2): No such
    file or directory in
    /home/content/t/i/m/timhish/h/i/s/h/html/test.php
    on line 5 Warning: Invalid argument
    supplied for foreach() in
    /home/content/t/i/m/timhish/html/test.php
    on line 15

    I changed ti from “/jobops”
    thinking it was a relative directory
    thing but apparently that’s not it. also
    im not sure what the
    /home/content……. thing is but i am
    currently hosted with go daddy maybe
    thats how they store things?

    The $directory variable is relative to where the script is being called. In my case, this runs from the root folder so it should be, for me, $directory = "jobops" assuming the folder and script are stored in the same place. Without knowing your server’s directory structure I can’t really help you, but I would suggest ruling out a problem with the scandir() function.

    To do this, create a folder in the same directory as your script called whatever you like, populate it with at least one image (so that the following if() doesn’t unset the entire array) and see if that works. If it does then you’re stuck with finding the relative path to your folder. If it doesn’t then I’m stuck myself.

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