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Home/ Questions/Q 7992015
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T13:27:21+00:00 2026-06-04T13:27:21+00:00

I’m really tired of syntax like this: .css(‘position’,’absolute’).css(‘z-index’,z-index) .css(‘border’,’1px solid #00AFFF’).css(‘margin’,’-1px 0px 0px -1px’)

  • 0

I’m really tired of syntax like this:

.css('position','absolute').css('z-index',z-index)
.css('border','1px solid #00AFFF').css('margin','-1px 0px 0px -1px')
.css('left',pleft)

I wonder if there’s any way to pass all parameters in one function, something like:

.foo('position':'absolute','z-index':z-index,
     'border':'1px solid #00AFFF','margin':'-1px 0px 0px -1px',
     'left':pleft)

Much appreciate any help.

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  1. Editorial Team
    Editorial Team
    2026-06-04T13:27:22+00:00Added an answer on June 4, 2026 at 1:27 pm

    Yes, pass an object to .css() (also mentioned in the docs):

    .css({
        position: 'absolute',
        left: pleft,
        zIndex: 123
        ...
    });
    

    Note that you can use both syntaxes for the keys: zIndex, i.e. the camelcase version that can be used directly in JavaScript and 'z-index' (quotes required as the - would break things otherwise).

    For options that are always the same – in your case probably position, border and margin – it might be a good idea to a classic CSS rule set via a class/id selector. Then you’d just have to set the remaining (dynamic) options via .css().

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