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Home/ Questions/Q 6717771
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T08:53:29+00:00 2026-05-26T08:53:29+00:00

I’m referencing two tables in the simple machines forum web forum software: smf_members, and

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I’m referencing two tables in the simple machines forum web forum software: smf_members, and smf_members. each row in smf_members has a field: id_group, of which I am interested in values: 1,9,20,26,23,27 (using the IN() clause). The general goal is to determine which rows in the smf_members table that are in the above group id’s haven’t had a row entered in smf_messages in 90 days. poster_time in smf_messages is a unix timestamp. What I have so far is:

SELECT
  m.id_member,
  m.id_group,
  from_unixtime(max(ms.poster_time))
FROM
  smf_members m
  LEFT JOIN smf_messages ms
    USING(id_member)
WHERE
  max(ms.poster_time) < (NOW() < (86400 * 90)
GROUP BY
  m.id_member

It fails with and ERROR 1111: Invalid use of the group function, since I am using max() in the where clause. How can I aggregate my join results to only reference the latest entry based off the poster_time field?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T08:53:30+00:00Added an answer on May 26, 2026 at 8:53 am

    There are several ways to this.

    1. SELECT * FROM members
      WHERE id_member IN ( … )
      AND NOT EXISTS
      ( SELECT 1 FROM messages
      WHERE is_member = members.id_member
      AND poster_time > (UNIX_TIMESTAMP*() – 90 * 24 * 60 * 60)

    2. look for the cases where an outer join finds nothing
      SELECT DISTINCT id_member
      FROM MEMBERS AS m …
      LEFT JOIN messages AS msg USING ….
      WHERE msg.id IS NULL

    3. SELECT * FROM members
      WHERE id_member IN ( …. )
      AND id_member NOT IN
      (SELECT id_member FROM messages
      WHERE poster_time > (UNIX_TIMESTAMP*() – 90 * 24 * 60 * 60)
      )

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