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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:28:14+00:00 2026-05-14T07:28:14+00:00

I’m relatively new to programming so excuse me if I get some terms wrong

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I’m relatively new to programming so excuse me if I get some terms wrong (I’ve learned the concepts, I just haven’t actually used most of them).

Trouble: I currently have a class I’ll call Bob its parent class is Cody, Cody has method call Foo(). I want Bob to have the Foo() method as well, except with a few extra lines of code. I’ve attempted to do Foo() : base(), however that doesn’t seem to work like. Is there some simple solution to this?

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:28:14+00:00Added an answer on May 14, 2026 at 7:28 am

    You can override Foo in the derived class and call the overridden base class implementation using base.Foo():

    class Cody
    {
        public virtual void Foo()
        {
            Console.WriteLine("Cody says: Hello World!");
        }
    }
    
    class Bob : Cody
    {
        public override void Foo()
        {
            base.Foo();
            Console.WriteLine("Bob says: Hello World!");
            base.Foo();
        }
    }
    

    Output of new Bob().Foo():

    Cody says: Hello World!
    Bob says: Hello World!
    Cody says: Hello World!
    

    Constructors use a slightly different syntax to call the constructor in a base class, because they have the requirement that the base class constructor must be called before the constructor in the derived class:

    class Cody
    {
        public Cody()
        {
        }
    }
    
    class Bob : Cody
    {
        public Bob() : base()
        {
        }
    }
    
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