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Home/ Questions/Q 9082249
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T20:30:50+00:00 2026-06-16T20:30:50+00:00

I’m returning a promise from a function like this: resultPromise = dgps.utils.save(opportunity, ‘/api/Opportunity/Save’, opportunity.dirtyFlag).then(function

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I’m returning a promise from a function like this:

resultPromise = dgps.utils.save(opportunity, '/api/Opportunity/Save', opportunity.dirtyFlag).then(function () {

                self.checklist.saveChecklist(opportunity).then(function () {

                    self.competitor.save(opportunity.selectedCompetitor()).then(function ... etc.
return resultPromise;

Let’s say the above function is called save.

In the calling function I want to do wait for the entire chain to complete and then do something. My code there looks like this:

var savePromise = self.save();
savePromise.then(function() {
    console.log('aftersave');
});

The result is that ‘aftersave’ is send to the console while the chain of promises is still running.

How can I do something after the whole chain is complete?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T20:30:51+00:00Added an answer on June 16, 2026 at 8:30 pm

    Instead of nesting the promises, chain them.

    resultPromise = dgps.utils.save(opportunity, '/api/Opportunity/Save', opportunity.dirtyFlag).then(function () {
    
                        return self.checklist.saveChecklist(opportunity);
                    }).then(function () {
    
                        return self.competitor.save(opportunity.selectedCompetitor());
                    }).then(function () {
                        // etc
                    });
    
    // return a promise which completes when the entire chain completes
    return resultPromise;
    
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