I’m running a mysqli query.
this is my code
<?php
$SM_pro_info="SELECT * FROM special_marketing_ads ORDER BY id desc LIMIT 4";
$QSM_pro_info = $db->query($SM_pro_info)or die($db->error);
if($QSM_pro_info->num_rows > 0){
while($SM_pro=$QSM_pro_info->fetch_object()){
?>
<table width="208" border="0">
<tr>
<td width="129" height="35" align="right"><span style="color:#361800; font-size:14px; font-weight:bold;"><?php echo $SM_pro->pro_title; ?></span></td>
<td width="69" rowspan="2" align="center"><a rel="lightbox" href="includes/Cpanel/projectImages//images.jpg" ><img src="<?php echo $SM_pro->image_1; ?>" alt="" width="60" height="60" border="0" /></a></td>
</tr>
<tr align="right">
<td><span style="color:#361800; font-size:14px; font-weight:bold;">الغرض</span> : <span style="color:#da6e19; font-size:15px; font-weight:bold;"><?php echo $SM_pro->pro_purpose; ?></span></td>
</tr>
</table>
<?php
}
}else{
for ($x=0; $x<(4 - $QSM_pro_info->num_rows); $x++) {
echo 'Your ad here'; // or, whatever your ad text is
}
}
?>
</div>
now all I want to do is if there is any results comeing from mysqli echo it if there is no results it should
echo an image which is add your ads here. the point is I have 4 Ads so if there is 1 Ads in mysqli row and the others is empty so I want it to echo this single Ads and the other 3 Ads should be this image add your Ads here.
any Help on this please?
Change this:
To this:
The issue is that you were checking for exactly one result. What you want is more than zero results.
Now, in the part where you display “your ads here”, try this:
Also be sure to use
htmlspecialchars()around your variable data in HTML, to avoid broken HTML (and potential XSS attacks, depending on your data source).