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Home/ Questions/Q 6625211
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T21:44:47+00:00 2026-05-25T21:44:47+00:00

i’m running inside http://llvm.org/demo the following snippet: class X { public: ~X() __attribute((nothrow)); };

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i’m running inside http://llvm.org/demo the following snippet:

class X { public: ~X() __attribute((nothrow)); };
void a(X* p);
void nothr() throw();
void b() { try { X x; a(&x); } catch (X* foo) { nothr(); } }

I see that some of the calls, (for instance, to func_llvm_eh_typeid_for) have the Attribute::NoUnwind set:

CallInst* int32_71 = CallInst::Create(func_llvm_eh_typeid_for, const_ptr_43, "", label_49);
  int32_71->setCallingConv(CallingConv::C);
  int32_71->setTailCall(false);
  AttrListPtr int32_71_PAL;
  {
   SmallVector<AttributeWithIndex, 4> Attrs;
   AttributeWithIndex PAWI;
   PAWI.Index = 4294967295U; PAWI.Attrs = 0  | Attribute::NoUnwind;
   Attrs.push_back(PAWI);
   int32_71_PAL = AttrListPtr::get(Attrs.begin(), Attrs.end());

  }
  int32_71->setAttributes(int32_71_PAL);

Since this calls are created with CallInst rather than InvokeInst, i presume the call themselves cannot throw, so it makes me wonder whats the purpose of the Unwind attribute in this context?

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  1. Editorial Team
    Editorial Team
    2026-05-25T21:44:48+00:00Added an answer on May 25, 2026 at 9:44 pm

    It means that you don’t have to worry about generating exception handling code or optimizing as if an exception could propagate through that section of code since you’ve already said it doesn’t. If one happens to come through there then it should propagate correctly through to the next stack frame in your program.

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