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Home/ Questions/Q 8022053
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T22:09:46+00:00 2026-06-04T22:09:46+00:00

I’m running on a scaled down version of CentOS 5.5 without many tools available.

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I’m running on a scaled down version of CentOS 5.5 without many tools available. No xxd, bc, or hd. I can’t install any additional utilities, unfortunately. I do have od, dd, awk, and bourne shell (not bash). What I’m trying to do is relatively simple in a normal environment. Basically, I have a number, say 100,000, and I need to store its binary representation in a file. Typically, I’d do something like …

printf '%x' "100000" | xxd -r -p > file.bin

If you view a hex dump of the file, you’d correctly see the number represented as 186A0.

Is there an equivalent I can cobble together using the limited tools I have available? Pretty much everything I’ve tried stores the ascii values for the digits.

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  1. Editorial Team
    Editorial Team
    2026-06-04T22:09:47+00:00Added an answer on June 4, 2026 at 10:09 pm

    You can do it with a combination of your printf, awk, and your shell.

    #!/usr/bin/env awk
    # ascii_to_bin.awk
    {
        # Pad out the incoming integer to a full byte
        len = length($0);
        if ( (len % 2) != 0) {
            str = sprintf("0%s", $0);
            len = len + 1;
        }
        else {
            str = $0;
        }
        # Create your escaped echo string
        printf("echo -n -e \"");
        for(i=1;i<=len;i=i+2) {
            printf("\\\\x%s", substr(str, i, 2));
        }
        printf("\"");
    }
    

    Then you can just do

    $ printf '%x' "100000" | awk -f ascii_to_bin.awk | /bin/sh > output.bin
    

    If you know your target binary length you can just do a printf "%0nX" (n is the target size) and remove the (len % 2) logic.

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